function_name()
call function_name()
ret function_name()
function function_name()
def fun (a = 2, b = 3, c)
def fun(a = 2, b, c = 3)
def fun(a, b = 2, c = 3)
def fun(a, b, c = 3, d)
What will be the output of the following python program?
def addItem(listParam): listParam+=[1]mylist=[1,2,3,4]addItem(mylist)print(len(mylist))
5
8
2
1
What is the value of the following Python code?
>>>print(36 / 4)
9
4
9.0
4.0
Required arguments
Keyword arguments
Default arguments
Variable-length arguments
What will be the output of the following Python code?
def foo(): total += 1 return totaltotal = 0print(foo())
0
error
none of the mentioned
find the output of following code:
def add(a,b): return(a+b)print(add(3,4))
7
What is the output of the following?
x=123for i in x: print(i)
1 2 3
123
Error
none of these
Arguments
Subroutines
Function
Definition
def foo(k): k[0] = 1 q = [0] foo(q) print(q)
[0]
[1]
[1, 0]
[0, 1]
Heap
Stack
Uninitialized data segment
None of the above
The variables used inside function are called local variables.
The local variables of a particular function can be used inside other functions, but these cannot be used in global space.
The variables used outside function are called global variables.
In order to change the value of global variable inside function, keyword global is used.
def foo(x): x = ['def', 'abc'] return id(x)q = ['abc', 'def']print(id(q) == foo(q))
True
False
None
What is the output of the following code?
def s(n1): print(n1) n1=n1+2n2=4s(n2)print(n2)
6 4
4 6
4 4
6 6
A built-in Python function
A one-line anonymous function
Lambda is a function in python but user can not use it.
procedure
function
bug
None of these
none
Null
Arbitary value
Define keyword in python
Define variable in python
Define function in python
All of the above
x='abcd'for i in x: print(i.upper())
a BCD
abcd
A B CD
def
fun
define
One
Two
Three
Any Number of Times
What will be the output of following?
Y=[2,5J,6]Y.sort()
[2,6,5J]
[5J,2,6]
[6,5J,2]
int
bool
void
What will be the output of the following Python code ?
def display(b,n): while n>0: print(b,end='') n=n-1display('z',3)
zzz
zz
Infinite loop
An exception is thrown
example = "helle" print(example.rfind("e"))
What is the output of the following
y='klmn'for i in range(len(y)): print(y)
klmn klmn klmn klmn
k
kkk
None of the these
x = 50def func (x): x = 2func (x)print ('x is now', x)
x is now 50
x is now 2
x is now 100
def foo(): return total + 1total = 0print(foo())
def function function_name():
declare function function_name():
def function_name():
declare function_name():
What is the return type of following function ?
def func1(): return 'mnp',22print(type(func1()))
List
Dictionary
String
Tuple
break
pass
continue
How many numbers will be printed by the following code?
def fun(a,b): for x in range(a,b+1): if x%3==0: print(x,end=" ")fun(100,120)
6
def foo(fname, val): print(fname(val))foo(max, [1, 2, 3])foo(min, [1, 2, 3])
3 1
1 3
A static variable
A global variable
A local variable
An automatic variable
What is the output of the following code ?
def fun(a, b=6): a=a+b print(a)fun(5, 4)
11
What is the output of below program ?
def say(message, times =1): print(message * times)say("Hello")say("Word",5)
Hello WordWordWordWordWord
Hello Word 5
Hello Word,Word,Word,Word,Word
Hello HelloHelloHelloHelloHello
null
An exception is thrown without the return statement
factorial()
print()
seed()
sqrt()
Parameters
def disp(*arg): for i in arg: print(i)disp(name="Rajat", age="20")
TypeError
Rajat 20
Name age