What will be the output of the following Python code?
d = {0, 1, 2}for x in d.values(): print(x)
0 1 2
None None None
error
none of the mentioned
What is the output of the following code?
a = set('dcma')b = set('mlpc')print(a^b)
{‘d’, ‘c’, ‘m’, ‘l’, ‘p’, ‘c’}
{‘m’, ‘l’, ‘p’, ‘c’}
{‘d’, ‘c’, ‘m’, ‘a’}
None of These
Mutable data type
Allows duplicate values
Data type with unordered values
Immutable data type
pop
remove
update
sum
discard
dispose
What will be the output of the following code snippet?
d={3,4,5} for k in d: print(k)
{3, 4, 5},{3, 4, 5}, {3, 4, 5}
3 4 5
syntax error
None of the above
Union
Intersection
Difference
set
tuple
string
s2.issubset(s1)
s2.issuperset(s1)
s1.issuperset(s2)
s1.isset(s2)
{ }
set()
[ ]
( )
s={abs}
s={4, ‘abc’, (1,2)}
s={2, 2.2, 3, ‘xyz’}
s={san}
d = {0, 1, 2}for x in d: print(d.add(x))
0 1 2 0 1 2 0 1 2 …
None of the mentioned
a={5,5,6,7}
a={5,6,7}
Error as there is no add function for set data type
Error as 5 already exists in the set
x | y
x ^ y
x & y
x – y
print(len(a))
print(min(a))
a.remove(5)
a[2]=45
>>> a={5,6,7}>>> sum(a,5)
5
23
18
Invalid syntax for sum method, too many arguments
{1, 2, 3}
[1, 2, 3]
{}
(1, 2, 3)
d = {0, 1, 2}for x in d: print(x)
{0, 1, 2} {0, 1, 2} {0, 1, 2}
List
Dictionary
Set
None of the Above
a={5,6,7,8}b={7,8,9,10} print(len(a+b))
8
Error, unsupported operand ‘+’ for sets
6
Nothing is displayed
What will the output of following code?
a={1,2,3}b={1,2,3,4}c=a.issuperset(b)print(c)
False
True
Syntax error for issuperset() method
Error, no method called issuperset() exists
keys, keys
key values, keys
keys, key values
key values, key values