What will be the output of the following Python code?
d1={"abc":5,"def":6,"ghi":7}print(d1[0])
abc
5
{"abc":5}
error
d = {0: 'a', 1: 'b', 2: 'c'}for i in d: print(i)
0 1 2
a b c
0 a 1 b 2 c
none of the mentioned
What will be the output of the following Python code snippet?
d = {"john":40, "peter":45}print(d["john"])
40
45
“john”
“peter”
a={1:"A",2:"B",3:"C"}b={4:"D",5:"E"}a.update(b) print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’}
Method update() doesn’t exist for dictionaries
{1: 'A', 2: 'B', 3: 'C', 4: 'D', 5: 'E'}
{4: ‘D’, 5: ‘E’}
a={1:"A",2:"B",3:"C"}a.setdefault(4,"D") print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}
None
Error
[1,3,6,10]
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(x)
String
Dictionary
List
Tuple
a={1:"A",2:"B",3:"C"}b=a.copy()b[2]="D" print(a)
Error, copy() method doesn’t exist for dictionaries
{1: ‘A’, 2: ‘D’, 3: ‘C’}
“None” is printed
The values of a dictionary can be accessed using keys
The keys of a dictionary can be accessed using values
Dictionaries aren’t ordered
Dictionaries are mutable
What is the output of the following code?
dict={"Joey":1, "Rachel":2}dict.update({"Phoebe":2})print(dict)
{'Joey': 1, 'Rachel': 2, 'Phoebe': 2}
{“Joey”:1,”Rachel”:}
{“Joey”:1,”Phoebe”:2}
d = {"john":40, "peter":45}print(list(d.keys()))
[“john”, “peter”]
[“john”:40, “peter”:45]
(“john”, “peter”)
(“john”:40, “peter”:45)
Clears all key-value pairs
Updates a specific key
Merges another dictionary into the current one
Removes all values
a={1:"A",2:"B",3:"C"}print(a.items())
Syntax error
dict_items([(‘A’), (‘B’), (‘C’)])
dict_items([(1,2,3)])
dict_items([(1, ‘A’), (2, ‘B’), (3, ‘C’)])
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 > d2)
True
False
test = {1:'A', 2:'B', 3:'C'}del test[1]test[1] = 'D'del test[2]print(len(test))
0
2
Error as the key-value pair of 1:’A’ is already deleted
1
a={1:"A",2:"B",3:"C"}print(a.get(1,4))
A
4
Invalid syntax for get method
a={'B':5,'A':9,'C':7}print(sorted(a))
[‘A’,’B’,’C’]
[‘B’,’C’,’A’]
[5,7,9]
[9,5,7]
What is the output of following code
d = {}d[1] = "Python"d[2] = "Java"print(len(d))
keys()
getkeys()
allkeys()
keyvalues()
a={} a[2]=1 a[1]=[2,3,4] print(a[1][1])
[2,3,4]
3
An exception is thrown
d.size()
len(d)
size(d)
d.len()
a={1:"A",2:"B",3:"C"}a.clear() print(a)
{ None:None, None:None, None:None}
{1:None, 2:None, 3:None}
{ }
More than one key isn’t allowed
Keys must be immutable
Keys must be integers
When duplicate keys encountered, the last assignment wins
Which of the following will delete key-value pair for key="tiger" in dictionary?
dic={"lion":"'wild","tiger":"'wild",'cat":"domestic","dog":"domestic"}
del dic("tiger")
dic["tiger"].delete()
delete(dic.["tiger'])
del dic["tiger"]
count={} count[(1,2,4)] = 5 count[(4,2,1)] = 7 count[(1,2)] = 6 count[(4,2,1)] = 2 tot = 0 for i in count: tot=tot+count[i] print(len(count)+tot)
25
17
16
Tuples can’t be made keys of a dictionary
numbers = {}letters = {}comb = {}numbers[1] = 56numbers[3] = 7letters[4] = 'B'comb['Numbers'] = numbers comb['Letters'] = lettersprint(comb)
Error, dictionary in a dictionary can’t exist
‘Numbers’: {1: 56, 3: 7}
{‘Numbers’: {1: 56}, ‘Letters’: {4: ‘B’}}
{‘Numbers’: {1: 56, 3: 7}, ‘Letters’: {4: ‘B’}}
Sequence value pair
Key value pair
Tuple value pair
Record value pair
a=dict()print(a[1])
An exception is thrown since the dictionary is empty
‘ ‘
Returns True if any key of the dictionary is true
Returns False if dictionary is empty
Returns True if all keys of the dictionary are true
Method any() doesn’t exist for dictionary
a={1:"A",2:"B",3:"C"}for i in a: print(i,end=" ")
1 2 3
‘A’ ‘B’ ‘C’
1 ‘A’ 2 ‘B’ 3 ‘C’
Error, it should be: for i in a.items():
del
remove
removeAll
None of these
d.delete(“john”:40)
d.delete(“john”)
del d[“john”]
del d(“john”:40)
What will be the output?
dict1={'a':[3,6,8]}print(len(dict1))
a={'a':4,'b':6,'a':7}print(a)
{'a': 5, 'b': 6,'a': 7 }
{'a': 7, 'b': 6}
{'a': 5, 'b': 6 }
Key Error
test = {1:'A', 2:'B', 3:'C'}test = {} print(len(test))
a={1:"A",2:"B",3:"C"}for i,j in a.items(): print(i,j,end=" ")
1 A 2 B 3 C
A B C
1:”A” 2:”B” 3:”C”
a = {}a[1] = 1a['1'] = 2a[1]=a[1]+1count = 0for i in a: count += a[i]print(count)
Error, the keys can’t be a mixture of letters and numbers
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(d[x])
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.keys(): print(d[x])
d.len ()
d = {"a": 1, "b": 2}print(2 in d)
KeyError
a={1:5,2:3,3:4}a.pop(3) print(a)
{1: 5}
{1: 5, 2: 3}
Error, syntax error for pop() method
{1: 5, 3: 4}
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 == d2)
d = {}
d = {“john”:40, “peter”:45}
d = {40:”john”, 45:”peter”}
All of the mentioned
More than one key can have the same value
The values of the dictionary can be accessed as dict[key]
Values of a dictionary must be unique
Values of a dictionary can be a mixture of letters and numbers
a = {} a[1] = 1 a['1'] = 2 a[1.0]=4 count = 0 for i in a: count += a[i] print(count) print(a)
6
Removes an arbitrary element
Removes all the key-value pairs
Removes the key-value pair for the key given as an argument
Invalid method for dictionary
total={}def insert(items): if items in total: total[items] += 1 else: total[items] = 1insert('Apple')insert('Ball')insert('Apple') print (len(total))
d = {"john":40, "peter":45}print("john" in d)