del
remove
removeAll
None of these
What will be the output of the following Python code?
a={1:"A",2:"B",3:"C"}print(a.items())
Syntax error
dict_items([(‘A’), (‘B’), (‘C’)])
dict_items([(1,2,3)])
dict_items([(1, ‘A’), (2, ‘B’), (3, ‘C’)])
What is the output of the following code?
a = {1:"A", 2: "B", 3: "C"}b = {4: "D", 5: "E"}a.update(b)print(a)
{1:’A’, 2: ‘B’,3: ‘C’}
{1: ‘A’, 2: ‘b’, 3: ‘c’, 4: ‘D’, 5: ‘E’}
Error
{4: ‘D’, 5: ‘E’}
a={'B':5,'A':9,'C':7}print(sorted(a))
[‘A’,’B’,’C’]
[‘B’,’C’,’A’]
[5,7,9]
[9,5,7]
What will be the output of the following Python code snippet?
a={1:"A",2:"B",3:"C"}print(a.get(3))
Error, invalid syntax
A
5
C
Which of the following will delete key-value pair for key="tiger" in dictionary?
dic={"lion":"'wild","tiger":"'wild",'cat":"domestic","dog":"domestic"}
del dic("tiger")
dic["tiger"].delete()
delete(dic.["tiger'])
del dic["tiger"]
test = {1:'A', 2:'B', 3:'C'}test = {} print(len(test))
0
None
3
An exception is thrown
a={}a['a']=1a['b']=[2,3,4] print(a)
Exception is thrown
{‘b’: [2], ‘a’: 1}
{‘b’: [2], ‘a’: [3]}
{'a': 1, 'b': [2, 3, 4]}
More than one key isn’t allowed
Keys must be immutable
Keys must be integers
When duplicate keys encountered, the last assignment wins
a = {}a[1] = 1a['1'] = 2a[1]=a[1]+1count = 0for i in a: count += a[i]print(count)
1
2
4
Error, the keys can’t be a mixture of letters and numbers
count={} count[(1,2,4)] = 5 count[(4,2,1)] = 7 count[(1,2)] = 6 count[(4,2,1)] = 2 tot = 0 for i in count: tot=tot+count[i] print(len(count)+tot)
25
17
16
Tuples can’t be made keys of a dictionary
a=dict()print(a[1])
An exception is thrown since the dictionary is empty
‘ ‘
d.size()
len(d)
size(d)
d.len ()
dictionary()
set()
tuple()
list()
d = {"john":40, "peter":45}print("john" in d)
True
False
d = {}
d = {“john”:40, “peter”:45}
d = {40:”john”, 45:”peter”}
All of the mentioned
Clears all key-value pairs
Updates a specific key
Merges another dictionary into the current one
Removes all values
d1={"abc":5,"def":6,"ghi":7}print(d1[0])
abc
{"abc":5}
error
d = {0: 'a', 1: 'b', 2: 'c'}for i in d: print(i)
0 1 2
a b c
0 a 1 b 2 c
none of the mentioned
d = {"john":40, "peter":45}print(list(d.keys()))
[“john”, “peter”]
[“john”:40, “peter”:45]
(“john”, “peter”)
(“john”:40, “peter”:45)
Sequence value pair
Key value pair
Tuple value pair
Record value pair
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.keys(): print(d[x])
getkeys()
key()
keys()
numbers = {}letters = {}comb = {}numbers[1] = 56numbers[3] = 7letters[4] = 'B'comb['Numbers'] = numbers comb['Letters'] = lettersprint(comb)
Error, dictionary in a dictionary can’t exist
‘Numbers’: {1: 56, 3: 7}
{‘Numbers’: {1: 56}, ‘Letters’: {4: ‘B’}}
{‘Numbers’: {1: 56, 3: 7}, ‘Letters’: {4: ‘B’}}
a={1:"A",2:"B",3:"C"}for i,j in a.items(): print(i,j,end=" ")
1 A 2 B 3 C
1 2 3
A B C
1:”A” 2:”B” 3:”C”
a={1:"A",2:"B",3:"C"}a.clear() print(a)
{ None:None, None:None, None:None}
{1:None, 2:None, 3:None}
{ }
The values of a dictionary can be accessed using keys
The keys of a dictionary can be accessed using values
Dictionaries aren’t ordered
Dictionaries are mutable
Since “susan” is not a value in the set, Python raises a KeyError exception
It is executed fine and no exception is raised, and it returns None
Since “susan” is not a key in the set, Python raises a KeyError exception
Since “susan” is not a key in the set, Python raises a syntax error
a={1:5,2:3,3:4}a.pop(3) print(a)
{1: 5}
{1: 5, 2: 3}
Error, syntax error for pop() method
{1: 5, 3: 4}
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 == d2)
a={} a[2]=1 a[1]=[2,3,4] print(a[1][1])
[2,3,4]
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(x)
allkeys()
keyvalues()
a={1:"A",2:"B",3:"C"}a.setdefault(4,"D") print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}
[1,3,6,10]
test = {1:'A', 2:'B', 3:'C'}del test[1]test[1] = 'D'del test[2]print(len(test))
Error as the key-value pair of 1:’A’ is already deleted
More than one key can have the same value
The values of the dictionary can be accessed as dict[key]
Values of a dictionary must be unique
Values of a dictionary can be a mixture of letters and numbers
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 > d2)
a={1:"A",2:"B",3:"C"}print(a.get(1,4))
Invalid syntax for get method
{1: ‘A’, 2: ‘B’}
dict([[1,”A”],[2,”B”]])
{1,”A”,2”B”}
d = {"john":40, "peter":45}print(d["john"])
40
45
“john”
“peter”
a={1:"A",2:"B",3:"C"}b={4:"D",5:"E"}a.update(b) print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’}
Method update() doesn’t exist for dictionaries
{1: 'A', 2: 'B', 3: 'C', 4: 'D', 5: 'E'}
dict={"Joey":1, "Rachel":2}dict.update({"Phoebe":2})print(dict)
{'Joey': 1, 'Rachel': 2, 'Phoebe': 2}
{“Joey”:1,”Rachel”:}
{“Joey”:1,”Phoebe”:2}
total={}def insert(items): if items in total: total[items] += 1 else: total[items] = 1insert('Apple')insert('Ball')insert('Apple') print (len(total))
a = {} a[1] = 1 a['1'] = 2 a[1.0]=4 count = 0 for i in a: count += a[i] print(count) print(a)
6
d.delete(“john”:40)
d.delete(“john”)
del d[“john”]
del d(“john”:40)
a={1:"A",2:"B",3:"C"}for i in a: print(i,end=" ")
‘A’ ‘B’ ‘C’
1 ‘A’ 2 ‘B’ 3 ‘C’
Error, it should be: for i in a.items():
Returns True if any key of the dictionary is true
Returns False if dictionary is empty
Returns True if all keys of the dictionary are true
Method any() doesn’t exist for dictionary
a={1:"A",2:"B",3:"C"}b=a.copy()b[2]="D" print(a)
Error, copy() method doesn’t exist for dictionaries
{1: ‘A’, 2: ‘D’, 3: ‘C’}
“None” is printed
Removes an arbitrary element
Removes all the key-value pairs
Removes the key-value pair for the key given as an argument
Invalid method for dictionary
getkeys ()