What will be the output of the following Python code snippet?
a={1:"A",2:"B",3:"C"}a.setdefault(4,"D") print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}
None
Error
[1,3,6,10]
del
remove
removeAll
None of these
d = {"john":40, "peter":45}print(list(d.keys()))
[“john”, “peter”]
[“john”:40, “peter”:45]
(“john”, “peter”)
(“john”:40, “peter”:45)
More than one key can have the same value
The values of the dictionary can be accessed as dict[key]
Values of a dictionary must be unique
Values of a dictionary can be a mixture of letters and numbers
dictionary()
set()
tuple()
list()
d = {}
d = {“john”:40, “peter”:45}
d = {40:”john”, 45:”peter”}
All of the mentioned
a={1:"A",2:"B",3:"C"}for i,j in a.items(): print(i,j,end=" ")
1 A 2 B 3 C
1 2 3
A B C
1:”A” 2:”B” 3:”C”
What will be the output of the following Python code?
a={1:5,2:3,3:4}a.pop(3) print(a)
{1: 5}
{1: 5, 2: 3}
Error, syntax error for pop() method
{1: 5, 3: 4}
More than one key isn’t allowed
Keys must be immutable
Keys must be integers
When duplicate keys encountered, the last assignment wins
a={1:"A",2:"B",3:"C"}print(a.items())
Syntax error
dict_items([(‘A’), (‘B’), (‘C’)])
dict_items([(1,2,3)])
dict_items([(1, ‘A’), (2, ‘B’), (3, ‘C’)])
a={}a['a']=1a['b']=[2,3,4] print(a)
Exception is thrown
{‘b’: [2], ‘a’: 1}
{‘b’: [2], ‘a’: [3]}
{'a': 1, 'b': [2, 3, 4]}
test = {1:'A', 2:'B', 3:'C'}del test[1]test[1] = 'D'del test[2]print(len(test))
0
2
Error as the key-value pair of 1:’A’ is already deleted
1
keys()
getkeys()
allkeys()
keyvalues()
Sequence value pair
Key value pair
Tuple value pair
Record value pair
a={1:"A",2:"B",3:"C"}for i in a: print(i,end=" ")
‘A’ ‘B’ ‘C’
1 ‘A’ 2 ‘B’ 3 ‘C’
Error, it should be: for i in a.items():
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 > d2)
True
False
{1: ‘A’, 2: ‘B’}
dict([[1,”A”],[2,”B”]])
{1,”A”,2”B”}
{ }
a={1:"A",2:"B",3:"C"}b={4:"D",5:"E"}a.update(b) print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’}
Method update() doesn’t exist for dictionaries
{1: 'A', 2: 'B', 3: 'C', 4: 'D', 5: 'E'}
{4: ‘D’, 5: ‘E’}
Since “susan” is not a value in the set, Python raises a KeyError exception
It is executed fine and no exception is raised, and it returns None
Since “susan” is not a key in the set, Python raises a KeyError exception
Since “susan” is not a key in the set, Python raises a syntax error
Removes an arbitrary element
Removes all the key-value pairs
Removes the key-value pair for the key given as an argument
Invalid method for dictionary
a={'B':5,'A':9,'C':7}print(sorted(a))
[‘A’,’B’,’C’]
[‘B’,’C’,’A’]
[5,7,9]
[9,5,7]
a = {}a[1] = 1a['1'] = 2a[1]=a[1]+1count = 0for i in a: count += a[i]print(count)
4
Error, the keys can’t be a mixture of letters and numbers
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(x)
0 1 2
a b c
0 a 1 b 2 c
none of the mentioned
numbers = {}letters = {}comb = {}numbers[1] = 56numbers[3] = 7letters[4] = 'B'comb['Numbers'] = numbers comb['Letters'] = lettersprint(comb)
Error, dictionary in a dictionary can’t exist
‘Numbers’: {1: 56, 3: 7}
{‘Numbers’: {1: 56}, ‘Letters’: {4: ‘B’}}
{‘Numbers’: {1: 56, 3: 7}, ‘Letters’: {4: ‘B’}}
What is the output of the following code?
a = {1:"A", 2: "B", 3: "C"}b = {4: "D", 5: "E"}a.update(b)print(a)
{1:’A’, 2: ‘B’,3: ‘C’}
{1: ‘A’, 2: ‘b’, 3: ‘c’, 4: ‘D’, 5: ‘E’}
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.keys(): print(d[x])
a={1:"A",2:"B",3:"C"}print(a.get(3))
Error, invalid syntax
A
5
C
getkeys ()
key()
d.size()
len(d)
size(d)
d.len ()
a={1:"A",2:"B",3:"C"}print(a.get(1,4))
Invalid syntax for get method
d = {"john":40, "peter":45}print("john" in d)
a={1:"A",2:"B",3:"C"}a.clear() print(a)
{ None:None, None:None, None:None}
{1:None, 2:None, 3:None}
d.len()
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 == d2)
Returns True if any key of the dictionary is true
Returns False if dictionary is empty
Returns True if all keys of the dictionary are true
Method any() doesn’t exist for dictionary
Clears all key-value pairs
Updates a specific key
Merges another dictionary into the current one
Removes all values
Which of the following will delete key-value pair for key="tiger" in dictionary?
dic={"lion":"'wild","tiger":"'wild",'cat":"domestic","dog":"domestic"}
del dic("tiger")
dic["tiger"].delete()
delete(dic.["tiger'])
del dic["tiger"]
d.delete(“john”:40)
d.delete(“john”)
del d[“john”]
del d(“john”:40)
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(d[x])
>>> a={1:"A",2:"B",3:"C"}>>> del a
method del doesn’t exist for the dictionary
del deletes the values in the dictionary
del deletes the entire dictionary
del deletes the keys in the dictionary
d = {0: 'a', 1: 'b', 2: 'c'}for i in d: print(i)
String
List
Tuple
Dictionary
a={} a[2]=1 a[1]=[2,3,4] print(a[1][1])
[2,3,4]
3
An exception is thrown
a = {} a[1] = 1 a['1'] = 2 a[1.0]=4 count = 0 for i in a: count += a[i] print(count) print(a)
6
d1={"abc":5,"def":6,"ghi":7}print(d1[0])
abc
{"abc":5}
error
The values of a dictionary can be accessed using keys
The keys of a dictionary can be accessed using values
Dictionaries aren’t ordered
Dictionaries are mutable
a=dict()print(a[1])
An exception is thrown since the dictionary is empty
‘ ‘
test = {1:'A', 2:'B', 3:'C'}test = {} print(len(test))
total={}def insert(items): if items in total: total[items] += 1 else: total[items] = 1insert('Apple')insert('Ball')insert('Apple') print (len(total))