What will be the output of the following Python code?
a={1:"A",2:"B",3:"C"}a.clear() print(a)
None
{ None:None, None:None, None:None}
{1:None, 2:None, 3:None}
{ }
d = {}
d = {“john”:40, “peter”:45}
d = {40:”john”, 45:”peter”}
All of the mentioned
What will be the output of the following Python code snippet?
d = {"john":40, "peter":45}print(list(d.keys()))
[“john”, “peter”]
[“john”:40, “peter”:45]
(“john”, “peter”)
(“john”:40, “peter”:45)
Since “susan” is not a value in the set, Python raises a KeyError exception
It is executed fine and no exception is raised, and it returns None
Since “susan” is not a key in the set, Python raises a KeyError exception
Since “susan” is not a key in the set, Python raises a syntax error
test = {1:'A', 2:'B', 3:'C'}test = {} print(len(test))
0
3
An exception is thrown
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.keys(): print(d[x])
0 1 2
a b c
0 a 1 b 2 c
none of the mentioned
a={'B':5,'A':9,'C':7}print(sorted(a))
[‘A’,’B’,’C’]
[‘B’,’C’,’A’]
[5,7,9]
[9,5,7]
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(d[x])
Clears all key-value pairs
Updates a specific key
Merges another dictionary into the current one
Removes all values
a={1:"A",2:"B",3:"C"}b=a.copy()b[2]="D" print(a)
Error, copy() method doesn’t exist for dictionaries
{1: ‘A’, 2: ‘B’, 3: ‘C’}
{1: ‘A’, 2: ‘D’, 3: ‘C’}
“None” is printed
The values of a dictionary can be accessed using keys
The keys of a dictionary can be accessed using values
Dictionaries aren’t ordered
Dictionaries are mutable
What is the output of the following code?
dict={"Joey":1, "Rachel":2}dict.update({"Phoebe":2})print(dict)
{'Joey': 1, 'Rachel': 2, 'Phoebe': 2}
{“Joey”:1,”Rachel”:}
{“Joey”:1,”Phoebe”:2}
Error
getkeys()
key()
keys()
Sequence value pair
Key value pair
Tuple value pair
Record value pair
total={}def insert(items): if items in total: total[items] += 1 else: total[items] = 1insert('Apple')insert('Ball')insert('Apple') print (len(total))
1
2
test = {1:'A', 2:'B', 3:'C'}del test[1]test[1] = 'D'del test[2]print(len(test))
Error as the key-value pair of 1:’A’ is already deleted
d = {0: 'a', 1: 'b', 2: 'c'}for i in d: print(i)
a={1:"A",2:"B",3:"C"}b={4:"D",5:"E"}a.update(b) print(a)
Method update() doesn’t exist for dictionaries
{1: 'A', 2: 'B', 3: 'C', 4: 'D', 5: 'E'}
{4: ‘D’, 5: ‘E’}
a={1:"A",2:"B",3:"C"}for i in a: print(i,end=" ")
1 2 3
‘A’ ‘B’ ‘C’
1 ‘A’ 2 ‘B’ 3 ‘C’
Error, it should be: for i in a.items():
d.size()
len(d)
size(d)
d.len ()
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 > d2)
True
False
a={} a[2]=1 a[1]=[2,3,4] print(a[1][1])
[2,3,4]
a={1:"A",2:"B",3:"C"}a.setdefault(4,"D") print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}
[1,3,6,10]
Removes an arbitrary element
Removes all the key-value pairs
Removes the key-value pair for the key given as an argument
Invalid method for dictionary
a = {1:"A", 2: "B", 3: "C"}b = {4: "D", 5: "E"}a.update(b)print(a)
{1:’A’, 2: ‘B’,3: ‘C’}
{1: ‘A’, 2: ‘b’, 3: ‘c’, 4: ‘D’, 5: ‘E’}
Which of the following will delete key-value pair for key="tiger" in dictionary?
dic={"lion":"'wild","tiger":"'wild",'cat":"domestic","dog":"domestic"}
del dic("tiger")
dic["tiger"].delete()
delete(dic.["tiger'])
del dic["tiger"]
a={1:"A",2:"B",3:"C"}print(a.get(1,4))
A
4
Invalid syntax for get method
a={1:5,2:3,3:4}a.pop(3) print(a)
{1: 5}
{1: 5, 2: 3}
Error, syntax error for pop() method
{1: 5, 3: 4}
String
List
Tuple
Dictionary
a={1:"A",2:"B",3:"C"}print(a.get(3))
Error, invalid syntax
5
C
d.delete(“john”:40)
d.delete(“john”)
del d[“john”]
del d(“john”:40)
a=dict()print(a[1])
An exception is thrown since the dictionary is empty
‘ ‘
Returns True if any key of the dictionary is true
Returns False if dictionary is empty
Returns True if all keys of the dictionary are true
Method any() doesn’t exist for dictionary
{1: ‘A’, 2: ‘B’}
dict([[1,”A”],[2,”B”]])
{1,”A”,2”B”}
d = {"john":40, "peter":45}print(d["john"])
40
45
“john”
“peter”
a={}a['a']=1a['b']=[2,3,4] print(a)
Exception is thrown
{‘b’: [2], ‘a’: 1}
{‘b’: [2], ‘a’: [3]}
{'a': 1, 'b': [2, 3, 4]}
More than one key isn’t allowed
Keys must be immutable
Keys must be integers
When duplicate keys encountered, the last assignment wins
More than one key can have the same value
The values of the dictionary can be accessed as dict[key]
Values of a dictionary must be unique
Values of a dictionary can be a mixture of letters and numbers
numbers = {}letters = {}comb = {}numbers[1] = 56numbers[3] = 7letters[4] = 'B'comb['Numbers'] = numbers comb['Letters'] = lettersprint(comb)
Error, dictionary in a dictionary can’t exist
‘Numbers’: {1: 56, 3: 7}
{‘Numbers’: {1: 56}, ‘Letters’: {4: ‘B’}}
{‘Numbers’: {1: 56, 3: 7}, ‘Letters’: {4: ‘B’}}
allkeys()
keyvalues()
d.len()
dictionary()
set()
tuple()
list()
d1={"abc":5,"def":6,"ghi":7}print(d1[0])
abc
{"abc":5}
error
d = {"john":40, "peter":45}print("john" in d)
a = {}a[1] = 1a['1'] = 2a[1]=a[1]+1count = 0for i in a: count += a[i]print(count)
Error, the keys can’t be a mixture of letters and numbers
a = {} a[1] = 1 a['1'] = 2 a[1.0]=4 count = 0 for i in a: count += a[i] print(count) print(a)
6
getkeys ()
count={} count[(1,2,4)] = 5 count[(4,2,1)] = 7 count[(1,2)] = 6 count[(4,2,1)] = 2 tot = 0 for i in count: tot=tot+count[i] print(len(count)+tot)
25
17
16
Tuples can’t be made keys of a dictionary
a={1:"A",2:"B",3:"C"}for i,j in a.items(): print(i,j,end=" ")
1 A 2 B 3 C
A B C
1:”A” 2:”B” 3:”C”
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(x)