What will be the output of the following Python code?
d = {0: 'a', 1: 'b', 2: 'c'}for i in d: print(i)
0 1 2
a b c
0 a 1 b 2 c
none of the mentioned
Since “susan” is not a value in the set, Python raises a KeyError exception
It is executed fine and no exception is raised, and it returns None
Since “susan” is not a key in the set, Python raises a KeyError exception
Since “susan” is not a key in the set, Python raises a syntax error
dictionary()
set()
tuple()
list()
a=dict()print(a[1])
An exception is thrown since the dictionary is empty
‘ ‘
1
0
What will be the output of the following Python code snippet?
total={}def insert(items): if items in total: total[items] += 1 else: total[items] = 1insert('Apple')insert('Ball')insert('Apple') print (len(total))
3
2
a={1:"A",2:"B",3:"C"}for i,j in a.items(): print(i,j,end=" ")
1 A 2 B 3 C
1 2 3
A B C
1:”A” 2:”B” 3:”C”
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 == d2)
True
False
None
Error
a={1:"A",2:"B",3:"C"}a.clear() print(a)
{ None:None, None:None, None:None}
{1:None, 2:None, 3:None}
{ }
d1={"abc":5,"def":6,"ghi":7}print(d1[0])
abc
5
{"abc":5}
error
d.size()
len(d)
size(d)
d.len ()
a={1:"A",2:"B",3:"C"}a.setdefault(4,"D") print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}
[1,3,6,10]
a={'B':5,'A':9,'C':7}print(sorted(a))
[‘A’,’B’,’C’]
[‘B’,’C’,’A’]
[5,7,9]
[9,5,7]
d.delete(“john”:40)
d.delete(“john”)
del d[“john”]
del d(“john”:40)
numbers = {}letters = {}comb = {}numbers[1] = 56numbers[3] = 7letters[4] = 'B'comb['Numbers'] = numbers comb['Letters'] = lettersprint(comb)
Error, dictionary in a dictionary can’t exist
‘Numbers’: {1: 56, 3: 7}
{‘Numbers’: {1: 56}, ‘Letters’: {4: ‘B’}}
{‘Numbers’: {1: 56, 3: 7}, ‘Letters’: {4: ‘B’}}
a={1:"A",2:"B",3:"C"}b={4:"D",5:"E"}a.update(b) print(a)
{1: ‘A’, 2: ‘B’, 3: ‘C’}
Method update() doesn’t exist for dictionaries
{1: 'A', 2: 'B', 3: 'C', 4: 'D', 5: 'E'}
{4: ‘D’, 5: ‘E’}
a = {} a[1] = 1 a['1'] = 2 a[1.0]=4 count = 0 for i in a: count += a[i] print(count) print(a)
An exception is thrown
6
a = {}a[1] = 1a['1'] = 2a[1]=a[1]+1count = 0for i in a: count += a[i]print(count)
4
Error, the keys can’t be a mixture of letters and numbers
test = {1:'A', 2:'B', 3:'C'}del test[1]test[1] = 'D'del test[2]print(len(test))
Error as the key-value pair of 1:’A’ is already deleted
d = {}
d = {“john”:40, “peter”:45}
d = {40:”john”, 45:”peter”}
All of the mentioned
The values of a dictionary can be accessed using keys
The keys of a dictionary can be accessed using values
Dictionaries aren’t ordered
Dictionaries are mutable
Which of the following will delete key-value pair for key="tiger" in dictionary?
dic={"lion":"'wild","tiger":"'wild",'cat":"domestic","dog":"domestic"}
del dic("tiger"]
dic["tiger"].delete()
delete(dic.["tiger'])
del(dic.["tiger"])
Removes an arbitrary element
Removes all the key-value pairs
Removes the key-value pair for the key given as an argument
Invalid method for dictionary
test = {1:'A', 2:'B', 3:'C'}test = {} print(len(test))
Clears all key-value pairs
Updates a specific key
Merges another dictionary into the current one
Removes all values
More than one key isn’t allowed
Keys must be immutable
Keys must be integers
When duplicate keys encountered, the last assignment wins
a={}a['a']=1a['b']=[2,3,4] print(a)
Exception is thrown
{‘b’: [2], ‘a’: 1}
{‘b’: [2], ‘a’: [3]}
{'a': 1, 'b': [2, 3, 4]}
d = {"john":40, "peter":45}print(d["john"])
40
45
“john”
“peter”
Returns True if any key of the dictionary is true
Returns False if dictionary is empty
Returns True if all keys of the dictionary are true
Method any() doesn’t exist for dictionary
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.values(): print(x)
a={1:"A",2:"B",3:"C"}print(a.get(1,4))
A
Invalid syntax for get method
a={1:"A",2:"B",3:"C"}print(a.get(3))
Error, invalid syntax
C
d = {"john":40, "peter":45}print(list(d.keys()))
[“john”, “peter”]
[“john”:40, “peter”:45]
(“john”, “peter”)
(“john”:40, “peter”:45)
d = {"john":40, "peter":45}print("john" in d)
{1: ‘A’, 2: ‘B’}
dict([[1,”A”],[2,”B”]])
{1,”A”,2”B”}
What is the output of the following code?
dict={"Joey":1, "Rachel":2}dict.update({"Phoebe":2})print(dict)
{'Joey': 1, 'Rachel': 2, 'Phoebe': 2}
{“Joey”:1,”Rachel”:}
{“Joey”:1,”Phoebe”:2}
d.len()
count={} count[(1,2,4)] = 5 count[(4,2,1)] = 7 count[(1,2)] = 6 count[(4,2,1)] = 2 tot = 0 for i in count: tot=tot+count[i] print(len(count)+tot)
25
17
16
Tuples can’t be made keys of a dictionary
a={1:"A",2:"B",3:"C"}for i in a: print(i,end=" ")
‘A’ ‘B’ ‘C’
1 ‘A’ 2 ‘B’ 3 ‘C’
Error, it should be: for i in a.items():
String
List
Tuple
Dictionary
del
remove
removeAll
None of these
More than one key can have the same value
The values of the dictionary can be accessed as dict[key]
Values of a dictionary must be unique
Values of a dictionary can be a mixture of letters and numbers
getkeys()
key()
keys()
d1 = {"john":40, "peter":45}d2 = {"john":466, "peter":45}print(d1 > d2)
a={1:"A",2:"B",3:"C"}b=a.copy()b[2]="D" print(a)
Error, copy() method doesn’t exist for dictionaries
{1: ‘A’, 2: ‘D’, 3: ‘C’}
“None” is printed
a={1:5,2:3,3:4}a.pop(3) print(a)
{1: 5}
{1: 5, 2: 3}
Error, syntax error for pop() method
{1: 5, 3: 4}
a={} a[2]=1 a[1]=[2,3,4] print(a[1][1])
[2,3,4]
a = {1:"A", 2: "B", 3: "C"}b = {4: "D", 5: "E"}a.update(b)print(a)
{1:’A’, 2: ‘B’,3: ‘C’}
{1: ‘A’, 2: ‘b’, 3: ‘c’, 4: ‘D’, 5: ‘E’}
getkeys ()
allkeys()
keyvalues()
d = {0: 'a', 1: 'b', 2: 'c'}for x in d.keys(): print(d[x])