list1.sum(5)
list1.add(5)
listl.append(5)
list1.addelement(5)
What is the output of following code
a=[1,2,3]a[::-1]print(a)
[1,2,3]
[3,2,1]
[2,1,3]
[3,1,2]
[0, 1, 2, 3]
[0, 1, 2, 3, 4]
[0.0, 0.5, 1.0, 1.5]
[0.0, 0.5, 1.0, 1.5, 2.0]
[3, 4, 5, 20, 5, 25, 1, 3]
[1, 3, 3, 4, 5, 5, 20, 25]
[3, 5, 20, 5, 25, 1, 3]
[1, 3, 4, 5, 20, 5, 25]
list1.remove(“hello”)
list1.remove(hello)
list1.removeAll(“hello”)
list1.removeOne(“hello”)
What will be the output of the following Python code snippet?
for i in [1, 2, 3, 4][::-1]: print (i)
1 2 3 4
4 3 2 1
error
none of the mentioned
list1.insert(3, 5)
list1.insert(2, 5)
list1.add(3, 5)
list1.append(3, 5)
What will be printed?
a = [[1, 2], [3, 4]]print(a[1][0])
1
2
3
4
It returns None.
It raises an IndexError
It creates a new element at that index.
It returns an empty list.
list1.append(5)
list1.addLast(5)
list1.addEnd(5)
[3, 4, 5, 20, 5, 25, 1, 3, 34, 5]
[1, 3, 3, 4, 5, 5, 20, 25, 34, 5]
[25, 20, 5, 5, 4, 3, 3, 1, 34, 5]
[1, 3, 4, 5, 20, 5, 25, 3, 34, 5]
arr[-2]
arr[2]
arr[-1]
arr[1]
list.contains(value)
list.index(value)
value in list
What will be the output of the following Python code?
data = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]def ttt(m): v = m[0][0] for row in m: for element in row: if v < element: v = element return vprint(ttt(data[0]))
5
places = ['Bangalore', 'Mumbai', 'Delhi'] places1 = places places2 = places[:] places1[1]="Pune" places2[2]="Hyderabad" print(places)
[‘Bangalore’, ‘Pune’, ‘Hyderabad’]
[‘Bangalore’, ‘Pune’, ‘Delhi’]
[‘Bangalore’, ‘Mumbai’, ‘Delhi’]
[‘Bangalore’, ‘Mumbai’, ‘Hyderabad’]
[25, 20, 5, 5, 4, 3, 3, 1]
[3, 1, 25, 5, 20, 5, 4, 3]
list1=[1,3]list2=list1list1[0]=4print(list2)
[1, 4]
[1,3, 4]
[4,3]
[1,3]
Appending
Concatenation
Deleting
Slicing
0
i.__add(j)
i.__add__(j)
i.__Add(j)
i.__ADD(j)
[‘h’, ‘e’, ‘l’, ‘l’, ‘o’]
[‘hello’]
[‘llo’]
[‘olleh’]
input(“Enter a string”)
eval(input(“Enter a string”))
enter(“Enter a string”)
eval(enter(“Enter a string”))
names = ['Amir', 'Bear', 'Charlton', 'Daman']print(names[-1][-1])
A
Daman
Error
n
What is the correct command to shuffle the following list?
fruit=['apple', 'banana', 'papaya', 'cherry']
fruit.shuffle()
shuffle(fruit)
random.shuffle(fruit)
random.shuffleList(fruit)
. List is mutable & Tuple is immutable
List is immutable & Tuple is mutable
Both are mutable
Both are immutable
matrix = [[1, 2, 3, 4], [4, 5, 6, 7], [8, 9, 10, 11], [12, 13, 14, 15]] for i in range(0, 4): print(matrix[i][1], end = " ")
4 5 6 7
1 3 8 12
2 5 9 13
What data type is the object below ?
L=[1, 23, 'hello', 1]
List
Dictionary
Tuple
Array
What will be the output?
a = [1, 2, 3]b = ab.append(4)print(a)
[1, 2, 3]
[1, 2, 3, 4]
[4]
a=[13,56,17] a.append([87]) a.extend([45,67]) print(a)
[13, 56, 17, [87], 45, 67]
[13, 56, 17, 87, 45, 67]
[13, 56, 17, 87,[ 45, 67]]
[13, 56, 17, [87], [45, 67]]
Returns None
Throws a KeyError
Creates a new key with a default value
Crashes the program
What will be the result?
a = [1, 2, 3]print(a[1:])
[1]
[2, 3]
[1, 2]
insert()
append()
extend()
add()
a= [1, 2, 3, 4, 5]for i in range(1, 5): a[i-1] = a[i]for i in range(0, 5): print(a[i],end = " ")
5 5 1 2 3
5 1 2 3 4
2 3 4 5 1
2 3 4 5 5
9
15
Built in
Derived data
x = [1, 2, 3]print(x[1:10])
[]
list1.addEnd (5)
list1.addLast (5)
list1.append (5)
values = [[3, 4, 5, 1], [33, 6, 1, 2]]v = values[0][0]for row in range(0, len(values)): for column in range(0, len(values[row])): if v < values[row][column]: v = values[row][column]print(v)
6
33
word1="Apple" word2="Apple" list1=[1,2,3] list2=[1,2,3] print(word1 is word2) print(list1 is list2)
True True
False True
False False
True False
What is the output of the following code?
list1=[2, 33, 222, 14, 25]print(list1[ : -1 ])
[2, 33, 222, 14]
25
[25, 14, 222, 33, 2]
list1 = list()
list1 = []
list1 = list([1, 2, 3])
all of the mentioned
Integer
String
myList = [1, 2, 3, 4, 5, 6]for i in range(1, 6): myList[i - 1] = myList[i] for i in range(0, 6): print(myList[i], end = " ")
2 3 4 5 6 1
6 1 2 3 4 5
2 3 4 5 6 6
1 1 2 3 4 5
x = [10, 20, 30]print(x * 0)
[0, 0, 0]
[ ]
x = ['ab', 'cd']for i in x: i.upper() print(x)
[‘ab’, ‘cd’]
[‘AB’, ‘CD’]
[None, None]
List is mutable & Tuple is immutable
Both List and Tuple are Mutable
Both List and Tuple are Immutable
a=["Apple","Ball","Cobra"]a.sort(key=len)print(a)
[‘Apple’, ‘Ball’, ‘Cobra’]
[‘Ball’, ‘Apple’, ‘Cobra’]
[‘Cobra’, ‘Apple’, ‘Ball’]
Invalid syntax for sort()
list=()
list.null
null.list
list=[]
{}
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