2445
133
12454
123
What will be the output of the following Python code?
list1 = [11, 2, 23]list2 = [11, 2, 2]print(list1 < list2)
True
False
Error
None
list1.remove(“hello”)
list1.remove(hello)
list1.removeAll(“hello”)
list1.removeOne(“hello”)
s.__len__()
len(s)
size(s)
s.size()
It returns None.
It raises an IndexError
It creates a new element at that index.
It returns an empty list.
input(“Enter a string”)
eval(input(“Enter a string”))
enter(“Enter a string”)
eval(enter(“Enter a string”))
['llo']
['hello']
['h', 'e', l', 'l', 'o']
None of the above
[3, 4, 5, 20, 5, 25, 1]
[1, 3, 3, 4, 5, 5, 20, 25]
[3, 5, 20, 5, 25, 1, 3]
[1, 3, 4, 5, 20, 5, 25]
insert()
append()
extend()
add()
list1.sum(5)
list1.add(5)
listl.append(5)
list1.addelement(5)
copy = list(original)
copy = original[:]
copy = original.copy()
All of the above
What is the output when we execute
list("hello") ?
['h', 'e', 'l', 'l', 'o']
[' hello']
['olleh']
0
1
4
2
list1.remove("hello")
list1.removeAll("hello")
list1.removeOne ("hello")
print(list1[0])
print(list1[:2])
print(list1[:-2])
all of the mentioned
[‘h’, ‘e’, ‘l’, ‘l’, ‘o’]
[‘hello’]
[‘llo’]
[‘olleh’]
List is mutable & Tuple is immutable
List is immutable & Tuple is mutable
Both List and Tuple are Mutable
Both List and Tuple are Immutable
values = [[3, 4, 5, 1 ], [33, 6, 1, 2]]for row in values: row.sort() for element in row: print(element, end = " ") print()
The program prints two rows 3 4 5 1 followed by 33 6 1 2
The program prints on row 3 4 5 1 33 6 1 2
The program prints two rows 1 3 4 5 followed by 1 2 6 33
Built in
List
Tuple
Derived data
myList = [1, 2, 3, 4, 5, 6]for i in range(1, 6): myList[i - 1] = myList[i] for i in range(0, 6): print(myList[i], end = " ")
2 3 4 5 6 1
6 1 2 3 4 5
2 3 4 5 6 6
1 1 2 3 4 5
a=[10,23,56,[78]] b=list(a) a[3][0]=95 a[1]=34 print(b)
[10,34,56,[95]]
[10,23,56,[78]]
[10,23,56,[95]]
[10,34,56,[78]]
data = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]def ttt(m): v = m[0][0] for row in m: for element in row: if v < element: v = element return vprint(ttt(data[0]))
5
list1 = list()
list1 = []
list1 = list([1, 2, 3])
What will be the output of the following ?
print((range(4)))
0,1,2,3
[0,1,2,3]
range(0, 4)
(0,1,2,3)
Heeeo
Heelo
Heleo
[3, 4, 5, 20, 5, 25, 1, 3]
what is the output of the following code?
M=['b' *x for x in range(4)] print(M)
['', 'b', 'bb', 'bbb']
['b,'bb', "bbb', "bbbb']
['b','bb', bbb']
none of these
What will be the output of the following code snippet?
a=[1,2,3,4,5,6,7,8,9]a[::2]=10,20,30,40,50,60print(a)
ValueError: attempt to assign sequence of size 6 to extended slice of size 5
[10, 2, 20, 4, 30, 6, 40, 8, 50, 60]
[1, 2, 10, 20, 30, 40, 50, 60]
[1, 10, 3, 20, 5, 30, 7, 40, 9, 50, 60]
What will be the output of the following Python code snippet?
for i in [1, 2, 3, 4][::-1]: print (i)
1 2 3 4
4 3 2 1
error
none of the mentioned
[25, 20, 5, 5, 4, 3, 3, 1]
[3, 1, 25, 5, 20, 5, 4, 3]
s[]
s.getitem(3)
s.__getitem__(3)
s.getItem(3)
[0, 1, 2, 3]
[0, 1, 2, 3, 4]
[0.0, 0.5, 1.0, 1.5]
[0.0, 0.5, 1.0, 1.5, 2.0]
a=["Apple","Ball","Cobra"]a.sort(key=len)print(a)
[‘Apple’, ‘Ball’, ‘Cobra’]
[‘Ball’, ‘Apple’, ‘Cobra’]
[‘Cobra’, ‘Apple’, ‘Ball’]
Invalid syntax for sort()
What is the output of the following code:
L=['a','b','c','d']print ( "".join(L))
abcd
[‘a’,’b’,’c’,’d’]
9
15
def f(values): values[0] = 44 v = [1, 2, 3]f(v)print(v)
[1, 44]
[1, 2, 3, 44]
[44, 2, 3]
[1, 2, 3]
. List is mutable & Tuple is immutable
Both are mutable
Both are immutable
list=()
list.null
null.list
list=[]
x = ['ab', 'cd']for i in x: i.upper() print(x)
[‘ab’, ‘cd’]
[‘AB’, ‘CD’]
[None, None]
a = [0, 1, 2, 3]for a[-1] in a: print(a[-1])
0 1 2 3
0 1 2 2
3 3 3 3
What data type is the object below ?
L=[1, 23, 'hello', 1]
Dictionary
Array
pop()
delete()
remove_last()
delete_last()
a= [1, 2, 3, 4, 5]for i in range(1, 5): a[i-1] = a[i]for i in range(0, 5): print(a[i],end = " ")
5 5 1 2 3
5 1 2 3 4
2 3 4 5 1
2 3 4 5 5
a=[13,56,17] a.append([87]) a.extend([45,67]) print(a)
[13, 56, 17, [87], 45, 67]
[13, 56, 17, 87, 45, 67]
[13, 56, 17, 87,[ 45, 67]]
[13, 56, 17, [87], [45, 67]]
list1.insert(3, 5)
list1.insert(2, 5)
list1.add(3, 5)
list1.append(3, 5)
myList = [1, 5, 5, 5, 5, 1]max = myList[0]indexOfMax = 0for i in range(1, len(myList)): if myList[i] > max: max = myList[i] indexOfMax = i print(indexOfMax)
3
What is the output of the following code?
list1=[2, 33, 222, 14, 25]print(list1[ : -1 ])
[2, 33, 222, 14]
25
[25, 14, 222, 33, 2]