list1.insert(3, 5)
list1.insert(2, 5)
list1.add(3, 5)
list1.append(3, 5)
list.contains(value)
list.index(value)
value in list
[3, 4, 5, 20, 5, 25, 1, 3]
[1, 3, 3, 4, 5, 5, 20, 25]
[3, 5, 20, 5, 25, 1, 3]
[1, 3, 4, 5, 20, 5, 25]
What will be the output of the following Python code?
a=["Apple","Ball","Cobra"]a.sort(key=len)print(a)
[‘Apple’, ‘Ball’, ‘Cobra’]
[‘Ball’, ‘Apple’, ‘Cobra’]
[‘Cobra’, ‘Apple’, ‘Ball’]
Invalid syntax for sort()
data = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]def ttt(m): v = m[0][0] for row in m: for element in row: if v < element: v = element return vprint(ttt(data[0]))
1
2
4
5
What will be the output of the following code snippet?
a=[1,2,3,4,5,6,7,8,9]a[::2]=10,20,30,40,50,60print(a)
ValueError: attempt to assign sequence of size 6 to extended slice of size 5
[10, 2, 20, 4, 30, 6, 40, 8, 50, 60]
[1, 2, 10, 20, 30, 40, 50, 60]
[1, 10, 3, 20, 5, 30, 7, 40, 9, 50, 60]
Built in
List
Tuple
Derived data
list1.addEnd (5)
list1.addLast (5)
list1.append (5)
list1.add(5)
arr[-2]
arr[2]
arr[-1]
arr[1]
list1 = [1, 3]list2 = list1list1[0] = 4print(list2)
[1, 3]
[4, 3]
[1, 4]
[1, 3, 4]
points = [[1, 2], [3, 1.5], [0.5, 0.5]]points.sort()print(points)
[[1, 2], [3, 1.5], [0.5, 0.5]]
[[3, 1.5], [1, 2], [0.5, 0.5]]
[[0.5, 0.5], [1, 2], [3, 1.5]]
[[0.5, 0.5], [3, 1.5], [1, 2]]
pop()
delete()
remove_last()
delete_last()
What will be the output of the following ?
print((range(4)))
0,1,2,3
[0,1,2,3]
range(0, 4)
(0,1,2,3)
a=[13,56,17] a.append([87]) a.extend([45,67]) print(a)
[13, 56, 17, [87], 45, 67]
[13, 56, 17, 87, 45, 67]
[13, 56, 17, 87,[ 45, 67]]
[13, 56, 17, [87], [45, 67]]
copy = list(original)
copy = original[:]
copy = original.copy()
All of the above
What is the output of the following code:
L=['a','b','c','d']print ( "".join(L))
Error
None
abcd
[‘a’,’b’,’c’,’d’]
print(list1[0])
print(list1[:2])
print(list1[:-2])
all of the mentioned
list1 = [11, 2, 23]list2 = [11, 2, 2]print(list1 < list2)
True
False
['llo']
['hello']
['h', 'e', T', '1', 'o']
None of the above
def f(values): values[0] = 44 v = [1, 2, 3]f(v)print(v)
[1, 44]
[1, 2, 3, 44]
[44, 2, 3]
[1, 2, 3]
0
list1.remove("hello")
list1.remove(hello)
list1.removeAll("hello")
list1.removeOne ("hello")
a=[1,2,3] b=a.append(4) print(a) print(b)
[1,2,3,4] [1,2,3,4]
[1, 2, 3, 4] None
Syntax error
[1,2,3] [1,2,3,4]
places = ['Bangalore', 'Mumbai', 'Delhi'] places1 = places places2 = places[:] places1[1]="Pune" places2[2]="Hyderabad" print(places)
[‘Bangalore’, ‘Pune’, ‘Hyderabad’]
[‘Bangalore’, ‘Pune’, ‘Delhi’]
[‘Bangalore’, ‘Mumbai’, ‘Delhi’]
[‘Bangalore’, ‘Mumbai’, ‘Hyderabad’]
What will be the output of the following code?
list1=[2,33,222,14,25]print(list1[-1])
33
14
25
[25, 20, 5, 5, 4, 3, 3, 1]
[3, 1, 25, 5, 20, 5, 4, 3]
input(“Enter a string”)
eval(input(“Enter a string”))
enter(“Enter a string”)
eval(enter(“Enter a string”))
i.__add(j)
i.__add__(j)
i.__Add(j)
i.__ADD(j)
list1.sum(5)
listl.append(5)
list1.addelement(5)
a= [1, 2, 3, 4, 5]for i in range(1, 5): a[i-1] = a[i]for i in range(0, 5): print(a[i],end = " ")
5 5 1 2 3
5 1 2 3 4
2 3 4 5 1
2 3 4 5 5
word1="Apple" word2="Apple" list1=[1,2,3] list2=[1,2,3] print(word1 is word2) print(list1 is list2)
True True
False True
False False
True False
List is mutable & Tuple is immutable
List is immutable & Tuple is mutable
Both List and Tuple are Mutable
Both List and Tuple are Immutable
9
15
What is the correct command to shuffle the following list?
fruit=['apple', 'banana', 'papaya', 'cherry']
fruit.shuffle()
shuffle(fruit)
random.shuffle(fruit)
random.shuffleList(fruit)
list1.shuffle()
shuffle(list1)
random.shuffle(list1)
random.shuffleList(list1)
[2, 6, 4]
[1, 3, 2, 1, 3]
[1, 3, 2, 1, 3, 2]
[1, 3, 2, 3, 2, 1]
list1 = list()
list1 = []
list1 = list([1, 2, 3])
myList = [1, 5, 5, 5, 5, 1]max = myList[0]indexOfMax = 0for i in range(1, len(myList)): if myList[i] > max: max = myList[i] indexOfMax = i print(indexOfMax)
3
[0, 1, 2, 3]
[0, 1, 2, 3, 4]
[0.0, 0.5, 1.0, 1.5]
[0.0, 0.5, 1.0, 1.5, 2.0]
myList = [1, 2, 3, 4, 5, 6]for i in range(1, 6): myList[i - 1] = myList[i] for i in range(0, 6): print(myList[i], end = " ")
2 3 4 5 6 1
6 1 2 3 4 5
2 3 4 5 6 6
1 1 2 3 4 5
list1=[1,3]list2=list1list1[0]=4print(list2)
[1,3, 4]
[4,3]
[1,3]
x = ['ab', 'cd']for i in x: i.upper() print(x)
[‘ab’, ‘cd’]
[‘AB’, ‘CD’]
[None, None]
none of the mentioned
What is the output when we execute
list("hello") ?
['h', 'e', 'l', 'l', 'o']
[' hello']
['olleh']
values = [[3, 4, 5, 1], [33, 6, 1, 2]]v = values[0][0]for lst in values: for element in lst: if v > element: v = elementprint(v)
6
[‘h’, ‘e’, ‘l’, ‘l’, ‘o’]
[‘hello’]
[‘llo’]
[‘olleh’]
list1.remove(“hello”)
list1.removeAll(“hello”)
list1.removeOne(“hello”)