What is the output of the following code ?
def disp(*arg):
for i in arg:
print(i)
disp(name="Rajat", age="20")
Qus
निम्नलिखित कोड का आउटपुट क्या होगा?
def disp(*arg): for i in arg: print(i) disp(name="Rajat", age="20")
A. TypeError
B. Rajat 20
C. Name age
D. None of these