char
int
float
double
results in a syntax error
output Infomax7
outputs garbage
outputs infomax and terminates abruptly
array
signed short
unsigned short
long
Binary operator
Unary operator
Ternary operator
All of the above
float, double
short int, double, long int
float, double, long double
double, long int, float
10
20
0
None
2
4
1
Depends on the system
A number
A special symbol other than underscore
Both of the above
An alphabet
&&
| |
!
What will be the output of the following code segment?
int x = 24, y = 39, z = 45;z = x + y;y = z - y;x = z - y;printf("\n%d %d %d", x, y, z);
24 39 63
39 24 63
24 39 45
39 24 45
It returns the size of the variable in bits
It returns the size of the variable in bytes
It returns the size of the variable in kilobytes
It returns the number of elements in an array
N=m=0
Value+=10
mySize=x<y?9:11
Value=+=10
* / % + - =
= * / % + -
/ * % - + =
* % / - + =
Logical Operator
Conditional Operator
typecast
Ternary
What is the output of the following code?
main(){ int a, b; a=b=4; b=a++; printf("%d %d %d %d", a++, --b, ++a, b--);}
5 3 7 3
Syntax error
5 4 5 3
6 2 6 4
8
16
Both can occur multiple times, but a declaration must occur first.
A definition occurs once, but a declaration may occur many times.
Both can occur multiple times, but a definition must occur first.
A declaration occurs once, but a definition may occur many times.
What will be the output of the following code?
int main(){int x,y,z;x='1'-'0'; /* line-1 */y='a'-'b'; /* line-2 */z=x+y;printf("%d",z);}
Error because of incorrect line-1 only.
Error because of incorrect line-1 and line-2.
Error because of incorrect line-2 only.
<
=
>=
<=
When the following piece of code is executed, what happens?
b = 3;a = b++;
a contains 3 and b contains 4
a contains 4 and b contains 4
a contains 4 and b contains 3
a contains 3 and b contains 3
4 Bytes
8 Bytes
Depends on the system/compiler
Cannot be determined
int a = 10, b = 20;printf("%d", a + b);
30
1020
10+20
Compiler error
*
+
++
int num;
integer num;
num int;
num integer;
int a = 10, b = 5;printf("%d", a / b);
5
0.5
15
char > int > float
int > char > float
char < int < double
double > char > int
getchar()
gets()
scanf()
cin.get()
Find the output of following code :
int main() { int i=-2; printf (“-i=%d”,-i); return b; }
–i=2
i=-2
–i=-2
–i=+2
int a = 5;printf("%d", a == 5);
Undefined
real
2 bytes
4 bytes
8 bytes
1 byte
it Compare the variable a and the variable b are same.
The value of b is assigned to variable a but if b changes later, it will not effect the value of variable a.
The value of b is assigned to variable a but if b changes later, it will effect the value of variable a.
The value of variable a is assigned to variable b, and the value of variable b is assigned to variable a.
2.5
2.000000
2.500000
getch()
getche()
Addition, Division, Modulus
Addition, Modulus, Division
Multiplication, Substration, Modulus
Modulus, Multiplication, Substration
What will be output if you will compile and execute the following c code?
int main(){ int a=5; float b; printf("%d",sizeof(++a+b)); printf(" %d",a); return 0;}
2 6
4 6
2 5
4 5
Either True or False
is less than or is more than
is equal or less or more
print("Hello World");
echo("Hello World");
printf("Hello World");
None of these
What will be output if you compile and execute the following ‘C’ code?
void main(){int i=4,x;x=++i + ++i + ++i;printf("%d",x);}
21
18
19
Compilation error
What is the output of this statement
printf("%d", (a++));
The value of (a + 1)
Error message
Garbage
The current value of a
printf("\n");
echo '\n';
printf('\n');
printf('\\n')
-3.4e38 to 3.4e38
-32767 to 32768
-32668 to 32667
-32768 to 32767
3
Decimal
Binary
Octal
Hexadecimal
&
||
int x = 5;printf("%d", ++x);
6
7