*
&
%
#
4
5
6
Undefined
What will be the output of the following program?
int main() { int x=5; printf(“%d %d %d”,x,x<<2,x>>2); }
1 20 5
5 1 20
5 20 1
20 1 5
2
1
Depends on the system
Binary operator
Unary operator
Ternary operator
All of the above
2 bytes
4 bytes
8 bytes
1 byte
10
20
0
None
-3.4e38 to 3.4e38
-32767 to 32768
-32668 to 32667
-32768 to 32767
&&
||
!
float
double
long double
far double
4 Bytes
8 Bytes
Depends on the system/compiler
Cannot be determined
When the following piece of code is executed, what happens?
b = 3;a = b++;
a contains 3 and b contains 4
a contains 4 and b contains 4
a contains 4 and b contains 3
a contains 3 and b contains 3
Logical Operator
Conditional Operator
typecast
Ternary
What is the output of the following code?
int a = 5;printf("%d", a == 5);
<
=
>=
<=
Find the output of following code :
int main() { int i=-2; printf (“-i=%d”,-i); return b; }
–i=2
i=-2
–i=-2
–i=+2
Decimal
Binary
Octal
Hexadecimal
What will be the output of the following code?
int a = 10, b = 20;printf("%d", a + b);
30
1020
10+20
Compiler error
int x = 5;printf("%d", ++x);
7
int a = 10, b = 5;printf("%d", a / b);
0.5
15
| |
print()
scanf()
input()
print("Hello World");
echo("Hello World");
printf("Hello World");
None of these
3
float, double
short int, double, long int
float, double, long double
double, long int, float
main(){ int a, b; a=b=4; b=a++; printf("%d %d %d %d", a++, --b, ++a, b--);}
5 3 7 3
Syntax error
5 4 5 3
6 2 6 4
What will be output if you compile and execute the following ‘C’ code?
void main(){int i=4,x;x=++i + ++i + ++i;printf("%d",x);}
21
18
19
Compilation error
signed short
unsigned short
long
int
+
++
char > int > float
int > char > float
char < int < double
double > char > int
-5
+5
What will be the output of the following code segment?
int x = 24, y = 39, z = 45;z = x + y;y = z - y;x = z - y;printf("\n%d %d %d", x, y, z);
24 39 63
39 24 63
24 39 45
39 24 45
getchar()
gets()
cin.get()
2.5
2.000000
2.500000
What is the output of the following code:
int x = 5;
printf("%d", x++);
What will be output if you will compile and execute the following c code?
int main(){ int a=5; float b; printf("%d",sizeof(++a+b)); printf(" %d",a); return 0;}
2 6
4 6
2 5
4 5
results in a syntax error
output Infomax7
outputs garbage
outputs infomax and terminates abruptly
N=m=0
Value+=10
mySize=x<y?9:11
Value=+=10
-4
-2.8
+2.8
+3
8
16
Either True or False
is less than or is more than
is equal or less or more
A number
A special symbol other than underscore
Both of the above
An alphabet
int main(){int x,y,z;x='1'-'0'; /* line-1 */y='a'-'b'; /* line-2 */z=x+y;printf("%d",z);}
Error because of incorrect line-1 only.
Error because of incorrect line-1 and line-2.
Error because of incorrect line-2 only.
What is the output of this statement
printf("%d", (a++));
The value of (a + 1)
Error message
Garbage
The current value of a
It returns the size of the variable in bits
It returns the size of the variable in bytes
It returns the size of the variable in kilobytes
It returns the number of elements in an array
-1
printf("\n");
echo '\n';
printf('\n');
printf('\\n')
int my_num = 100,000;
int my_num = 100000;
int my num = 1000;
int $my_num = 10000;
The basic data type of C
Qualifier
Short is the qualifier and int is the basic data type
All of the mentioned